Question

A truck travelling at 30 km/h speeds up to 90 km/h in 6 seconds. What is the acceleration of the truck?

Answer 1

Answer:

a=v-u/t

90-30/6

60/6

10km/hr

Explanation:

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Answer 2

Answer:

Initial velocity (u) = 30km/h = 30×5/18 = 25/3m/s

Final velocity (v) = 90km/h = 90×5/18 = 25m/s

As known,

$a = \frac{v - u}{t}$

Putting values,

$a \: = \frac{ 25 - \frac{25}{3} }{6}$

By taking lcm ;

$a = \frac{ \frac{25 \times 3 - 25}{3} }{6}$

$a = \frac{ \frac{50}{3} }{6}$

$a = \: \frac{25}{9}$

thus,

a = 2.78 ms^(-2) {Approx.}