Question

A trucks speed increases from est to 35m/s in 30s .It travels in one direction Find the magnitude of acceleration of the truck at the ditances it traveled. Show your solution.

Answer 1

Answer: Acceleration=7/6m/s^2 =1.167m/s^2 approx.

Distance=525m

Explanation:

Initial Velocity, u=0m/s (The truck starts from rest)

Final Velocity, v=35m/s

Time, t=30s

We know that v=u+at

35=0+(a)(30)

a=7/6m/s^2

=1.167m/s^2 approx.

We also know that v^2-u^2=2aS

1225=2(7/6)(S)

S=525m