Question

A TUBE LIGHT DRAWS 0.1A CURRENT FROM A 220 V SUPPLY.WHT CURRENT WILL THIS TUBE LIGHT DRAW WHEN IT IS CONNECTED TO A 110 V SUPPLY?

Answer 1

Answer:

0.05

Explanation:

I =0.1

V=220

applying ohms law

R=V/I

R=2200

putting value of R in

V=110

R=2200

I= V/R

I= 110/2200

I=0.05

Answer 2

Concept:

Ohm's Law: Ohm's law states that the potential difference across any conductor is directly proportional to the current flowing through the conductor. Mathematically, it can be expressed as follows -

V $\propto$ I

V = IR

where V = Potential difference

I = Current

R = Proportionality constant called resistance measured in ohm.

Resistance is the obstruction in the path of the flow of current.

Given:

First Case: Tube light is connected to 220 V.

Potential difference, V₁ = 220 V

Current, I₁ = 0.1 A

Second Case: Tube light is connected to 110 V suppy.

Potential difference, V₂ = 110 V

Find:

Current drawn by Tube light in second case.

Solution:

For first case, let the resistance of the Tube light be R.

Applying Ohm's law, we get

V₁  = I₁R

R = V₁/I₁

R  = 220/0.1

R = 2200 Ω

In second case, let the  current drawn by the Tube light be I₂.

Again applying Ohm's law, we have

V₂ = I₂R            [ Resistance is same as it is a constant]

I₂ = V₂/R

I₂ = 110/2200

I₂ = 0.05 A

Hence, the current drawn by the tube light when it is connected to a 110 V supply is 0.05 A.

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