Question

A tuning fork and an air column whose temperature is 51C produce 4beats in one second., when sounded together. When the temperature of air column decreases the no.of beats per second decreases. When the temperature remains 16C only one beat per second is produced. The frequency of tuning fork is

1- 100Hz 2-75Hz 3-150Hz 4- 50Hz

Answer 1

when temp. decreases, speed of sound in air decreases, since no. of beats per second is less at lower tempertaure we coclude that frequency of aircolumn is higher than freq. of tuning fork.

let v be freq. of tuning fork, then at 51 degrees frq. of air column will be (n+4) where n is freq. of tuning fork

at 16 degrees , frewq. of air column will be (n+1)

v51/v16 = (n+4)*k / (n+1)*k

(n+4)/(n+1) = (273+51)1/2 / (273+16)1/2

on solving ofr n , we'll get n = 50 Hz

Answer 2

Answer:

50Hz

Explanation:

v+4/v+1=√273+51/273+16