A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz. The first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?
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Hello dear,
● Answer- 252 Hz
● Explaination-
# Given-
n1 = 256 Hz
n2 = unknown
b1 = 4 Hz
b2 = 6 Hz
# Solution-
Initially,
n2 = n1 + b or n1 - b
n2 = 256 + 4 or 256 - 4
n2 = 260 Hz or 252 Hz
After putting wax, frequency of tuning fork will decrease. n2' < n2 .
(I) Taking n2 = 260 ,
n2' = 256 + 6 = 262 Hz
Here, n2' > n2 which is not the case in added wax.
(II) Taking n2 = 252 Hz,
n2' = 256 - 6 = 250 Hz
Here, n2' < n2 ,which is the case for wax adding.
Hope this is useful..
● Answer- 252 Hz
● Explaination-
# Given-
n1 = 256 Hz
n2 = unknown
b1 = 4 Hz
b2 = 6 Hz
# Solution-
Initially,
n2 = n1 + b or n1 - b
n2 = 256 + 4 or 256 - 4
n2 = 260 Hz or 252 Hz
After putting wax, frequency of tuning fork will decrease. n2' < n2 .
(I) Taking n2 = 260 ,
n2' = 256 + 6 = 262 Hz
Here, n2' > n2 which is not the case in added wax.
(II) Taking n2 = 252 Hz,
n2' = 256 - 6 = 250 Hz
Here, n2' < n2 ,which is the case for wax adding.
Hope this is useful..
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