A turn of radius 20m is banked for the vehicle of mass 200kg going at a speed of 10m/s. Find the direction and magnitude of frictional force acting on a vehicle if it moves with a speed of 15m/s
Answers
Answered by
5
The turn is banked for speed v = 10 m/s therefore
As the speed is decreased force of friction f acts upwards
Substituting, v=5 m/s, m=200kg, r=20m
Here force of friction f will act downwards
Substituting v=15 m/s,, m=200kg and r=20m we get
As the speed is decreased force of friction f acts upwards
Substituting, v=5 m/s, m=200kg, r=20m
Here force of friction f will act downwards
Substituting v=15 m/s,, m=200kg and r=20m we get
cvrohit:
finish the answer
Answered by
3
see attachment....hope it will help u
Attachments:
Similar questions