A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.
Answers
Given :-
- Distance between Them = 360m .
- Move Towards each other at = 3pm.
- Speed of turtle = 11 * speed of snail.
- Meets at = 3:40PM .
To Find :-
- Speed of Each ?
Solution :-
→ Let Speed of Snail = x m/min.
→ Speed of Turtle = 11x m/min.
→ Usual Speed of Both in Opposite Direction = x + 11x = 12x m/min.
→ Time taken by them = 3:40 - 3:00 = 40min.
→ Total Distance covered = 360m .
So,
→ Speed * Time = Distance .
Putting values we get :-
→ 12x * 40 = 360
→ 480x = 360
→ x = (360/480)
→ x = (3/4) m / min.
Hence,
→ Speed of Snail = x m/min. = (3/4) m /min.
→ Speed of Turtle = 11x m/min. = 11 * (3/4) = (33/4) m /min.
Answer:-
Let the speed of Snail be "S" m/s
Speed of the turtle = 11S m/s
given,
distance between them = 360 m
Time taken to meet each other = 40 min = 40*60 = 2400 sec.
We know that,
Speed = Distance/time
Speed of the snail = 360/2400
Speed of the snail = 0.15 m/s (or) 0.54 km/h
Speed of the turtle = 11S = 11(0.15) = 1.65 m/s (or) 5.94 km/h.
Therefore, the speed of Snail is 0.15 m/s and speed of the turtle is 1.65 m/s.