A TV set is being sold for Rs. x in Chandigarh. A deal went to Delhi and bought the TV at 20% discount (fro the price of Chandigarh). He spent Rs. 600 transport. Thus he sold the set in Chandigarh for Rs 2 making 14% profit. What was x?
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Quantitative Aptitude
Profit and Loss
Successive Selling
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A TV set is being sold for Rs. X in Delhi. A dealer went to Chandigarh and bought the TV at 20% discount (from the price of Delhi). He spends Rs. 600 on transport. Thus, he sold the set in Delhi for Rs. X making (100/7) % profit what is the value of X?
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RRC Group D Previous Paper 1 (Held On: 17 Sep 2018 Shift 1)
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Rs. 7200
Rs. 8000
Rs. 8800
Rs. 9600
Answer (Detailed Solution Below)
Option 2 : Rs. 8000
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Detailed Solution
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Given :
A TV set selling price in Delhi = Rs. X
The discount is given on TV set in Chandigarh = 20%
Profit % = 100/7% = %
Transportation cost = Rs. 600
Formula Used:
Selling price = Cost Price × (100 + P%)/100
Calculation:
CP = 80% of X = 0.8X
According to the question
⇒ X = [0.8X + 600 (100 + 100/7)]/100
⇒ X = [(0.8X + 600)(800/7)]/100
⇒ 100X = [(0.8X + 600)(800)]/7
⇒ 700X = (0.8X + 600)(800)
⇒ 700X = 640X + 48000
⇒ 60X = 48000
⇒ X = 8000
∴ The value of X is Rs.8000
⇒ Selling Price of TV in Chandigarh = X – 20% of X = Rs. 0.8X
⇒ Total cost price of TV in Delhi = 0.8X + 600
⇒ Selling Price = Rs. X
⇒ Profit% = {(X – 0.8X – 600)/(0.8X + 600)} × 100
⇒ 100/7 = {(0.2X – 600) / (0.8x + 600)} × 100
⇒ 0.8X + 600 = 1.4X – 4200
⇒ X = 8000