Question

A TV towehas a height of 200 m. How

much population is covered by TV

transmission if the average population

density around the tower is 1000/

? (Radius of the Earth m)​

Answer 1

Answer:

Solid angle subtended: w=2π(1−cosθ)=2π(1−  

R+h

R

​  

)

Now, area covered: A=wR  

2

=2πR  

2

(1−  

R+h

R

​  

)=2πR  

2

(  

R+h

h

​  

)

For h<<R⟹A=2πhR

Thus, net population covered: N=Area×population density=2πhR×ρ    

Given: ρ=100 km  

−2

=100×10  

−6

 m  

−2

=10  

−4

 m  

−2

 

N=2(3.14)×100×6.37×10  

6

×10  

−4

 

⟹N=4×10  

5

=4 lakh  

Explanation: