A two digit no. is seven times the sum of its digits. The no. formed by reversing the digits is 18 less than the original no. Find the no.
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let the unity place be x and ten's place be y
A/q,
10x+y=7(x+y)-------------(i)
Now interchanging its digits
10y+x=7(x+y)-18---------(ii)
solving (i)
10x+y=7x+7y
x=2y
putting x=2y in ----(ii)
12y+=21y-18
-9y= -18
y=2
so x=2y -------
x=4
Now putting value of x and y in (i)
10×4+2
42.------correct answer
A/q,
10x+y=7(x+y)-------------(i)
Now interchanging its digits
10y+x=7(x+y)-18---------(ii)
solving (i)
10x+y=7x+7y
x=2y
putting x=2y in ----(ii)
12y+=21y-18
-9y= -18
y=2
so x=2y -------
x=4
Now putting value of x and y in (i)
10×4+2
42.------correct answer
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