Question

A two digit number and the number with digits interchanged add up to 143. In the given number

the digit in unit’s place is 3 more than the digit in the ten’s place. Find the original number. by linear equation in two variable method
plzz it's urgent​

Answer 1

Answer:

Here you go......... When u reverse the digits it becomes 10y + x

Answer 2

Let the number at the unit's place the x and the digit at the ten's place y.

The number is thus 10y + x

After interchanging the digits the number becomes 10 x + y

Given that two digit number and the number with digits are interchanged add up to 143.

So 10y + x + 10 x + y = 143

↝ 11 x + 11 y = 143

↝ x + y = 13.......eq1

Also in the given number the digit in unit's place in 3 more than the digit in the ten's place.

So,

x - y = 3.....eq2

Adding equation 1 and 2 we have

2x = 16

↝ x = 8

Putting the value of x in equation 1 we get

8 + y = 13

↝ y = 13 - 8

↝ y = 5 (ans)

Thus, the number is 58.

ĦØ₱Ɇ Ɨ₮ ĦɆⱠ₱$ ¥ØɄ

❤₮Ħ₳₦Ԟ ¥ØɄ ❤