Question

A two digit number and the number with digits interchanged add up 143. In the given number the digit in unit's place is 3 more than digit in the ten's place. Find the original number.

Answer 1

the orignal nber is 58 if u interchange it and add ,58 + 85 = 143

Answer 2

Answer:

58

Step-by-step explanation:

Given : A two digit number and the number with digits interchanged add up 143. In the given number the digit in unit's place is 3 more than digit in the ten's place.

To Find:Find the original number.

Solution:

Let the digit on ten's place be x

Let digit on unit's place be y

Number = xy

Since we are given that  the digit in unit's place is 3 more than digit in the ten's place.

y-x=3 ---a

Since we are given that  A two digit number and the number with digits interchanged add up 143.

⇒(10x+y)+(10y+x)=143

⇒11x+11y=143 ---b

Solving a and b using sbstitution method

Substitute value of y from a in b

⇒11x+11(x+3)=143

⇒11x+11x+33=143

⇒22x=110

⇒x=110/22

⇒x=5

So, ten's place digit is 5

Unit's place digit = x+3=5+3=8

So, the number is 58