Question

a two-digit number becomes five-sixth of itself when it's digits are reversed. the digits are differ by one, find the number ​

Answer 1

Let the number at Tens place be x.Then, digit at unit place =(x-1)

The required number = 10x +x - 1

=> 11x-1

A/c

$10(x-1)+x= \frac{5}{6} (11x - 1 ) \\ = > 10x - 10 + x = \frac{5}{6} (11x - 1) \\ \\ = > 6(11x - 10) = 5(11x - 1) \\ = > 66x - 60 = 55x - 5 \\ = > 66x - 55x = 60 - 5 \\ = > 11x = 55 \\ = > x = 5.$

Hence,the required number is 56