Math, asked by ankityadav36, 1 year ago

a two-digit number becomes five-sixth of itself when it's digits are reversed. the digits are differ by one, find the number ​

Answers

Answered by arc555
5

Let the number at Tens place be x.Then, digit at unit place =(x-1)

The required number = 10x +x - 1

=> 11x-1

A/c

10(x-1)+x= \frac{5}{6} (11x - 1 ) \\  =  > 10x - 10 + x =  \frac{5}{6} (11x - 1) \\  \\  =  > 6(11x - 10) = 5(11x - 1) \\  =  > 66x - 60 = 55x - 5 \\  =  > 66x - 55x = 60 - 5 \\  =  > 11x = 55 \\  =  > x = 5. \\

Hence,the required number is 56

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