Question

A two digit number contains the smaller of the two digits in the units place. The product of the digits is 40 and the difference between the digits is 3. Find the number. topic :Quadratic equation

Answer 1

Let the two digit number will be first x and second is y

The two digit number is 10x+y

xy=40

x=

y

40

x−y=3 --- (i)

y

40

−y=3

y

2

+3y−40=0

y

2

+8y−5y−40=0

y(y+8)−5(y+8)=0

y=5 as it cannot be −8

From (i)

x−5=3 ⟹ x=8

⟹ The two digit number is 10x+y=10(8)+5=85

please mark me the brainliest I have no brainliest answers...