Question

A two-digit number exceeds the sum of the digits of that number by 18. if the digit at the unit's place is double the digit in the ten's place, what is the number?

Answer 1

Solution -

Let the tens place digit be x and unit place digit be y.

Therefore, the two digit number is 10x + y.

Given

10x + y = x + y + 18 

9x = 18 

x = 2.

Also given y = 2x = 2 * 2 = 4

Therefore, the two digit number = 10x + y =  10 * 2 + 4  = 24

Answer 2

Answer:

24

Step-by-step explanation:

let me clear-

let 10 place digit be y and unit place digit be z

then,

10y+z=y+z+18

9y=18

y=2

ATQ,

z=2z=2×2=4

so, two digit number =10y+z= 10×2+4=24