A two digit number havina two digit number having y in ones place and x in then place isg y in ones place and x in then place is
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The digit in the tens place...
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Asked on December 20, 2019 by
Amber Devgharkar
The digit in the tens place of a two-digit number is four times the digit in the units place. When the digits are reversed, the number obtained is 27 less than the original numbers. Find the original number.
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Let the original number be xy=10x+y
Digit's on 10
′
s place=x
Digit in units place=y
Given that x=4y
reversed number yx=10y+x
yx=xy−27
10y+x=10x+y−27
9x=9y+27
x=y+3
x=4y
4y=y+3
3y=3
y=1
x=4(1)=4
∴ original number=4
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