A two digit number is 3 more than 4 times the sum of its digit.If 18 is added to this number, the sum is equal to the number obtained by interchanging the digits.find the number.
Answers
Answered by
3
let the digits be x and y
the number = 4(x+y) + 3
ATQ
4(x+y) + 3 + 18 = 10y + x
4x + 4y + 21 = 10y + x
3x - 6y + 21 = 0
x - 2y + 7 = 0
x = 2y - 7
now
10x + y = 4(x+y) + 3
6x - 3y - 3 = 0
2x - y - 1 = 0
2(2y - 7 ) - y - 1 = 0
4y - 14 - y - 1 = 0
3y = 15
y = 5
now
x = 2y - 7 = 2(5)-7 = 3
the number is 35
the number = 4(x+y) + 3
ATQ
4(x+y) + 3 + 18 = 10y + x
4x + 4y + 21 = 10y + x
3x - 6y + 21 = 0
x - 2y + 7 = 0
x = 2y - 7
now
10x + y = 4(x+y) + 3
6x - 3y - 3 = 0
2x - y - 1 = 0
2(2y - 7 ) - y - 1 = 0
4y - 14 - y - 1 = 0
3y = 15
y = 5
now
x = 2y - 7 = 2(5)-7 = 3
the number is 35
Answered by
2
Let y be the unit’s digit and x be the tens digit....so we have 10x+y=3+4(x+y)....10x+y=3+4x+4y.....6x-3y=3......2x-y=1
According to the second condition we have: 10x+y+18=10y+x.....9x-9y=-18......x-y=-2......subtract (x-y=-2) from (2x-y=1)....we get x=3....substituting the value of x in x-y=-2,we get y=5...hence the number is 35
According to the second condition we have: 10x+y+18=10y+x.....9x-9y=-18......x-y=-2......subtract (x-y=-2) from (2x-y=1)....we get x=3....substituting the value of x in x-y=-2,we get y=5...hence the number is 35
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