a two digit number is 3 more than 4 times the sum of its digits if 18 is added to the number it gets digits are reversed find the number
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let the digit at once digit be x
and tens place be y
then
10y+x
when digit reversed
it becomes
10x+y
case 1
10y+x=4(x+y)+3
10y+x=4x+4y+3
10y+x-4x-4y=3
6y-3x=3....... ( both side divided by 3)
2y-x=1________(1)
case 2
(10y+x)+18=10x+y
10y+x-10x-y=18
9x-9y=18......... ( both side divided by 9)
x-y=2________(2)
x=2+y
put the value of x in equation (1)
2y-X=1
2y-(2+y)=1
2y-2-y=1
y=3
put value of y in equation 2
x-y=2
x-3=2
x=5
then the number is
10y+x= 10*3+5
=35
Thanks
let the digit at once digit be x
and tens place be y
then
10y+x
when digit reversed
it becomes
10x+y
case 1
10y+x=4(x+y)+3
10y+x=4x+4y+3
10y+x-4x-4y=3
6y-3x=3....... ( both side divided by 3)
2y-x=1________(1)
case 2
(10y+x)+18=10x+y
10y+x-10x-y=18
9x-9y=18......... ( both side divided by 9)
x-y=2________(2)
x=2+y
put the value of x in equation (1)
2y-X=1
2y-(2+y)=1
2y-2-y=1
y=3
put value of y in equation 2
x-y=2
x-3=2
x=5
then the number is
10y+x= 10*3+5
=35
Thanks
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