Question

a two digit number is 3 more than 7 times the sum of its digt then how much such number are there?​

Answer 1

Step-by-step explanation:

if the number is >ab

given 10a +b= 7 (a+b)+3

or ,3a =6 b +3

or,a,=2,b +1

b ,can take values .0,1,2,3 and 4

then a,=1,3 ,5,7,9 respectively

thus the answer are 10,31,52,73,94