A two digit number is 4 times the sum of its digits and 2 times the product of it's digits. Calculate the number.
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Hi friend
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Your answer
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Let the digit at the ones place be y and the digit at the tens place be x.
Then, the number = 10x + y
Now,
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SOLVING (BY METHOD OF SUBSTITUTION)
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According to the question,
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Equations : -
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10x + y = 4(x + y) .....(i)
10x + y = 2xy......(ii)
From equation (i), we get,
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10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x = 4y - 3y
=> 6x = 3y
=> x = 3y/6
=> x = y/2 ......(iii)
Now,
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Substituting the value of x from equation (iii) in equation (ii), we get,
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10x + y = 2xy
=> 10 × y/2 + y = 2 × y/2 × y
=> 5y + y = y²
=> 6y = y²
=> y = 6
Now,
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Putting the value of y in equation (ii),we get,
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x = y/2
=> x = 6/2
=> x = 3
Therefore,
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The number = 10x + y = (10 × 3) + 6 = 30 + 6 = 36
-------------
Your answer
---------------------
Let the digit at the ones place be y and the digit at the tens place be x.
Then, the number = 10x + y
Now,
----------
SOLVING (BY METHOD OF SUBSTITUTION)
-----------------------------------------------------------------
According to the question,
----------------------------------------
Equations : -
------------------
10x + y = 4(x + y) .....(i)
10x + y = 2xy......(ii)
From equation (i), we get,
---------------------------------------
10x + y = 4(x + y)
=> 10x + y = 4x + 4y
=> 10x - 4x = 4y - 3y
=> 6x = 3y
=> x = 3y/6
=> x = y/2 ......(iii)
Now,
----------
Substituting the value of x from equation (iii) in equation (ii), we get,
---------------------------------------------------------------------------------------------------
10x + y = 2xy
=> 10 × y/2 + y = 2 × y/2 × y
=> 5y + y = y²
=> 6y = y²
=> y = 6
Now,
--------
Putting the value of y in equation (ii),we get,
----------------------------------------------------------------
x = y/2
=> x = 6/2
=> x = 3
Therefore,
------------------
The number = 10x + y = (10 × 3) + 6 = 30 + 6 = 36
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