Question

A two digit number is 7 times the sum of its digits. The number formed by reversing the digits is 18 less than the original number. Find the number.​

Answer 1

Step-by-step explanation:

A two digit number is seven times the sum of its digits, the ... ⇒10x+y=7(x+ y) 10x+y=7x+7y 3x=6y x=2y the number formed by reversing the digits is 18 less than ...

Answer 2

Answer:

$\large{\red{\underline{\tt{Answer}}}}$

let the two-digit number be 10x+y

given,the number is 7 times the sum of its digits

⇒10x+y=7(x+y)

10x+y=7x+7y

3x=6y

x=2y

the number formed by reversing the digits is 18 less than original number

⇒10x+y-(10y+x)=18

10x+y-10y-x=18

9x-9y=18

9(x-y)=18

(x-y)=18/9=2

⇒x-y=2

x=2y

⇒2y-y=2

y=2

x=4

∴the number is 42

$\huge\underline\mathfrak\red{thanks}$