Question

a two digit number is chosen at random . find the probability that it is a prime number ​

Answer 1

$\huge\mathcal\pink{\boxed{\boxed{\boxed{Hola\:mate}}}}$

$\huge\sf\purple{Good \: morning}$

$\huge\mathcal\green{\boxed{Answer\:---}}$

Total No. of outcomes = 90

No. of favourable outcomes = 23 ( 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 57, 59, 61, 67, 71, 73, 83, 87, 89, 91, 97 )

P( prime number) = 23 / 90

$\huge\mathcal\purple{Hope\: it \:helps\:....}$

$\huge\mathcal\purple{Please\:mark\:as\:the}$

$\huge\mathcal\green{\boxed{\boxed{brainliest\: (rate)}}}$

$\huge\mathcal\purple{and\:follow}$

Answer 2

The probability of selecting a 2-digit prime number is 21/90

Step-by-step explanation:

Total number of 2 digit numbers are (99-10)+1 = 90

The number of prime numbers out of the 90 2-digit numbers are 21, i.e., 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89 and 97.

Probability of selecting a prime 2-digit number, P = No. of 2-digit prime numbers / Total number of 2-digit numbers

P = 21 / 90

Thus, the probability of selecting a 2-digit prime number is 21/90