A two digit number is equal to 7 times of the sum of it's digits.The number formed by reversing it's digits is less than the original number by 18.Find the original number
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Answer:
The seven is the orignal number
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10x+y=7(x+y)
3x-6y=0
x-2y=0
10y+x=10x+y-18
Substitute the values of x and y
3x-6y=0
x-2y=0
10y+x=10x+y-18
Substitute the values of x and y
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