Question

A two digit number is obtained by either multiplying the sum of its digits by 8 and adding 1 or multiplying difference of digits by 13 and adding 2.Find the number. ​

Answer 1

Answer:

$let \: no \: be \: xy \\ according \: to \: the \: question \\ (x + y)8 + 1 = xy \\ and \\ (x - y)13 + 2 = xy \\ so \\ (x + y)8 + 1 = (x - y)13 + 2 \\ 8x + 8y + 1 = 13x - 13y+ 2 \\ 21y = 5x + 1 \\ x = (21y - 1) \div 5 \\ now \: puting \: value \\ (21y - 1 ) \div 5 \times 8+ 8y + 1 = xy \\ 29y = \times$

Answer 2

Answer:

The answer is in the attached picture.

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