Extra Questions for Maths, chapter 7 -Triangles......Class 9
Answers
Ok ur question in this attachment.
Question from foundation course.
Answer:
Here are the first several prime factors: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29...
Let's start by dividing 5,005 by 2
5,005 ÷ 2 = 2,502.5 - This has a remainder. Let's try another prime number.
5,005 ÷ 3 = 1,668.3333 - This has a remainder. Let's try another prime number.
5,005 ÷ 5 = 1,001 - No remainder! 5 is one of the factors!
1,001 ÷ 5 = 200.2 - There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number
1,001 ÷ 7 = 143 - No remainder! 7 is one of the factors!
143 ÷ 7 = 20.4286 - There is a remainder. We can't divide by 7 evenly anymore. Let's try the next prime number
143 ÷ 11 = 13 - No remainder! 11 is one of the factors!
13 ÷ 11 = 1.1818 - There is a remainder. We can't divide by 11 evenly anymore. Let's try the next prime number
13 ÷ 13 = 1 - No remainder! 13 is one of the factors!
The orange divisor(s) above are the prime factors of the number 5,005. If we put all of it together we have the factors 5 x 7 x 11 x 13 = 5,005. It can also be written in exponential form as 51 x 71 x 111 x 131.