A two digit number is seven times the sum of its digits and is equal to 12 less than three times the product of its digit. find the number
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7
let one digit be x
∴other digit= 7- x
∴no. = 10x + 7 - x = 9x+7
∴9x+7 = {3×x(7-x)}-12
or,9x+7+12 = 3×(7x-x²)
or,9x+19 = 21x-3x²
now you can do it
∴other digit= 7- x
∴no. = 10x + 7 - x = 9x+7
∴9x+7 = {3×x(7-x)}-12
or,9x+7+12 = 3×(7x-x²)
or,9x+19 = 21x-3x²
now you can do it
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