A two-digit number is such that it is equal to four times the sum of its digits. The number formed by interchanging the digits of such a number is how many times the sum of its digits
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Answer:
solution is as follows
Step-by-step explanation:
let the two digit number be 10x + y
given,
4(x+y)=10x+y
4x+4y=10x+y
3y=6x
y=2x
so,
10y+x=20x+1x
=7(x+y)
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