Question

A two-digit number is such that the digit in units place is double the digit in tens place. If 18 is added the the number, the digit interchange their places. Find the number.
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Answer 1

Answer

Given,

• Digit in unit place is double the digit in tens place
• Digits interchange their places when 18 is added

To find,

• The original number

Solution ,

Let the digit at tens place be 'x'

Let the digit at tens place be 'x' Let the digit at ones place be 'y'

Hence original number will be:

10x + y

According to the question :

y = 2x ---------(1)

Also,

Interchanging the digits of original number we get: 10y + x

⇛ (10x + y) + 18 = 10y + x

⇛ 10x + y + 18 = 10y + x

⇛ 9x - 9y + 18 = 0

Dividing the equation by '9'

We get,

⇛ x - y + 2 = 0 -----------(2)

Putting y = 2x in equation (2)

We get,

⇛ x - 2x + 2 = 0

⇛ -x + 2 = 0

⇛ x = 2

Putting x = 2 in equation (1)

We get

⇛ y = 2(2)

⇛ y = 4

Hence the original number will be:

⇛ 10(2) + 4

⇛ 20 + 4

⇛ 24

So, Our original number is 24

Answer 2

Step-by-step explanation:

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