A two digit number is such that the product of it's digit is 35.if 8 is added fo the number, the digits interchange their places .find the in numbers
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Let x be the ones digit and y be the tenth digit
xy=35
The number is equal to 10y+x
If 18 is added
10y +x+ 18
digit are interchanged so the number is xy, 10x+y
so 10y +x+ 18 = 10x+y
solve the two equations
9y-9x+18=0
y-x-2=0
x=y-2
xy=35
(y-2)(y)=35
y^2 -2y-35 =0
(y-7) (y+5) =0
y=7 so x = 5
y = -5 is rejected since -5 is negative
∴ The number is 35
Hope This Helps :)
xy=35
The number is equal to 10y+x
If 18 is added
10y +x+ 18
digit are interchanged so the number is xy, 10x+y
so 10y +x+ 18 = 10x+y
solve the two equations
9y-9x+18=0
y-x-2=0
x=y-2
xy=35
(y-2)(y)=35
y^2 -2y-35 =0
(y-7) (y+5) =0
y=7 so x = 5
y = -5 is rejected since -5 is negative
∴ The number is 35
Hope This Helps :)
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