Question

A two digit number is such that the product of its digits is
18. When 63 is subtracted from the number, The digits interchange their
places. Find the number.

Answer 1

Let the A two digit number be (10x+y)

The product of its digits is 18 so,

$x*y=18$
$x=18/y$....................(1)

When 63 is subtracted from the number, The digits interchange their places, so

$10x+y-63=10y+x$

subsitute

$10*18/y+y-63=10y+18/y$

$180/y+y-63=10y+18/y$

multiply through by y to eliminate the fractions

$180+y^2-63y=10y^2+18$

collect terms

$10y^+18=y^2-63y+180$

$9y^2 +63y -162 = 0$

divide by 9

$y^2+7y -18=0$

Now just factor the equation and you will get the value of X and y thenyour untimate number will be (10x+Y).

Answer 2

Answer: good one

Step-by-step explanation: