A two-digit number is three times the sum of its digits. Then the unit place digit of the number is:
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Answer:
The answer is:
Step-by-step explanation:
Let the unit place of the number = x
and the ten place = y
The number will be =10y+x
According to question
10y+x=3(x+y)
10y+x=3x+3y
7y−2x=0 ......(i)
Again
(10y+x)+45=10x+y
10y+x+45=10x+y
9y−9x=−45
x−y=5 ........(ii)
x=5+y
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