Question

a two digit number of which 10 digit exceeds unit digit by 5 the number itself is 8 times the sum of its digits find the number​

Answer 1

Let tens digit be x

ones digit be y

Number = 10x+y

By conditions,

x=y+5 ------(1)

10x+y = 8(x+y)

10x+y=8x+8y

2x=7y -------(2)

Substituting (1) in (2),

2(y+5) = 7y

2y + 10 = 7y

5y=10

y=2

x =y+5

x= 2+5 = 7

Therefore the number is 72

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Answer 2

Answer:

72

Step-by-step explanation:

take x and y in equation Andrew