a two digit number of which tens digit exceeds unit digit by 5 the number itself is 8 times the number of its digits find the number
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Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,
y=x+6
10y+x=10(x+y)
10y+x=10x+10y
x−10x=0⇒x=0
y=0+6⇒y=6
the given number is
10×6+0=60
Step-by-step explanation:
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