Question

A two digit number with digits interchanged add up to 143. In the given number the digit in units place is 3 more than the digit in the tens place. Find the original number

Answer 1

let digit at tens place = x
∴ digit at ones place =x+3

original number = 10(x)+(x+3)
⇒new number = 10(x+3)+x
∴According to question
  10(x)+(x+3)+10(x+3)+x=143
⇒10x+x+3+10x+30+x=143
⇒22x+33=143
⇒11(2x+3)=11*13
⇒2x+3=13
⇒2x=13-3
⇒2x=10
⇒x=10/2
⇒x=5
         (ANSWER)