A two dijit no is such that the product of its digits is 12 and when 36 is added it reverses
Answers
Answered by
0
Answer:
Step-by-step explanation:
Let the digits be x and y
xy = 12 ……. I
The number is 10x+y
So, (10x + y) + 36 = 10y + x
then: 9x - 9y = -36
Divide through by 9
So, x - y = -4 ……. II
x = y - 4 ….. III
put III in I
(y - 4)y = 12
y²- 4y -12 = 0
(y² - 6y) + (2y - 12) = 0
y(y - 6) + 2(y - 6) = 0
y = -2 or y = 6
From III, x = y - 4
When y = -2,
x = -2 - 4 = -6
When y = 6
x = 6 - 4 = 2
(x,y) = (-6, -2) or (2, 6)
Therefore, the number 10x + y
Is, 10(-6) + (-2) = -60–2= -62
And, 10(2) + (6) = 26
Check: 6 x 2 = 12 and -6 x (-2) = 12
Also: -62 + 36 = -26
And: 26 + 36 = 62
The number is -62 or 26
Answered by
0
The number is -62 or 26
Thanks!!!!
Similar questions