A two dogit number is such that the product of its digits is 12.if 36 is added to the number, its digit are reversed.what is that number?
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Number is 26
Explanation:
Let the unit's digit in the number be x, then as product of digits is 12, the ten's digit in the number is 12x.
Hence, the value of the number is 10×12x+x=120x+x
On reversing the digits, unit's digit becomes ten's digit and ten's digit becomes unit's digit and its value will become
10x+12x
It is apparent that 10x+12x is greater than 120x+x by 36
Hence 10x+12x=120x+x+36
or 9x=120−12x+36
or 9x=108x+36 and dividing each term by 9 we get
x=12x+4 and now multiply each by x to get
x2=12+4x or x2−4x−12=0
i.e. x2−6x+2x−12=0
or x(x−6)+2(x−6)=0
i.e. (x+2)(x−6)=0
Hence, x=−2 or x=6
But we cannot have negative number in units place
Hence, 6 is in unit's place and in ten's place we have 126=2
and number is 26
Regards ♡♡《 Nitish kr 》♡♡
Mate ________€€€____
Her is the ans ______€€
Number is 26
Explanation:
Let the unit's digit in the number be x, then as product of digits is 12, the ten's digit in the number is 12x.
Hence, the value of the number is 10×12x+x=120x+x
On reversing the digits, unit's digit becomes ten's digit and ten's digit becomes unit's digit and its value will become
10x+12x
It is apparent that 10x+12x is greater than 120x+x by 36
Hence 10x+12x=120x+x+36
or 9x=120−12x+36
or 9x=108x+36 and dividing each term by 9 we get
x=12x+4 and now multiply each by x to get
x2=12+4x or x2−4x−12=0
i.e. x2−6x+2x−12=0
or x(x−6)+2(x−6)=0
i.e. (x+2)(x−6)=0
Hence, x=−2 or x=6
But we cannot have negative number in units place
Hence, 6 is in unit's place and in ten's place we have 126=2
and number is 26
Regards ♡♡《 Nitish kr 》♡♡
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