A typical car weight about 1200N. if the coefficient rolling friction. is 0.015 what horizontal force is a need to make the car move with constant speed 72km/h on a level road ? also calculate the power devloped by the engine maintain and this speed.
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Answer:
Friction Force = Normal weight× coefficient of rolling friction
Friction Force = 1200×0•015 = 12×1•5 = 18 N-m
Kinetic energy = 1/2 mv^2
v =72kmph = 72×1000/3600 = 20 m/s
K. E, = 0•5×1200×400 = 240000 N-m
Total power developed by engine = 240018 N-m
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