A U atom, emits a particles If, at any instant an alpha particle is at a distance of 9x10 m from the centre of the disintegrated atom, then what will be the force acting on
the alpha particle.
ans:512N
give me the solution
Answers
Answered by
1
Answer:
512N you now that solution you right that why your asking
Answered by
4
Answer:
hello...
bro.....
this is your answer.......
Parent nuclei is U 92 - 238
Emitted particle = He 2- 4
Remaining daughter nuclei = X 92 − 2^238 − 4 = X 90^234
Charge of daughter nuclei = 90 × charge on proton
charge on alpha particle = 2 × charge on proton
Distance between them r = 9 × 10^−15 m
Electric force of repulsion between them
F = k q2 × q1 / r^2
F = 9 × 10^9 × 90 × 2 × (1.6 × 10^−19)^2 / (9 × 10^−15)^2
F = 51.2 × 10 = 512 N
Hence the force on the alpha particle is 512 N
0.0
hope this will help you mate............
mark me as brainliest........
pleaseeeeee........
AKAL ACADEMY GOMTI....STUDENT's
LOVEPREET SINGH......
Similar questions