Question

A 'U' tube differential nanometer connect two pressure pipe A and B. pipe A contain carbon tetrachloride having specific gravity 1.594 under a pressure of 11.772N/cm*2 and pipe B contain oil of specific gravity 0.8 under pressure of 11.772 N/cm*2 . the pipe a lies 2.5 m above pipe B. Find the difference of pressure measured by mercury 'U'tube manometer.​

Answer 1

$\Delta h_m=0.293\ m$ is the equivalent mercury head

$P=39053\ Pa$ is the pressure difference

Explanation:

Given:

• specific gravity of carbon tetra-chloride in pipe A, $S_a=1.594$

• specific gravity of coil in pipe B, $S_b=0.8$

• differential height of pipe A above B, $\Delta h_a=2.5\ m$

Now pressure due to differential head:

$P=\rho_a.g.\Delta h_a$

$P=1594\times 2.5\times 9.8$

$P=39053\ Pa$

where:

$\rho_a=$ density of carbon tetra-chloride

For the equivalent mercury height we form the equation as:

$\rho_a.g.\Delta h_a=\rho_m.g.\Delta h_m$

subscript m is for mercury,

we have density of mercury as 13600 kg per cubic meter

$1594\times 2.5=13600\times \Delta h_m$

$\Delta h_m=0.293\ m$

TOPIC: relative density, pressure head

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