A u-tube of base length l filled with same volume of two liquids of densities t and 2t is moving with acceleration a on horizontal plane. If the height difference between two surfaces(open to atmosphere) becomes zero then height h is given by
Answers
Answer:
Explanation:
The pressures at the bottoms of the left hand side and right hand side columns are ,
P1=P0+2ρgh andP2=P0+ρghP1=P0+2ρgh andP2=P0+ρgh
Where P0 is the atmospheric pressure .
The pressure at the left hand side must be greater because a net force to the right is needed to accelerate the liquid in the horizontal part of the tube .
The masses in the left hand side and the right hand side of the liquid is 2ρ(L2)A and ρ(L2)A 2ρL2A and ρL2A where A is the cross sectional area of the tube .
The difference between the pressures in the left hand side and right hand side of the horizontal section is ρghρgh .
This must be sufficient to accelerate the mass of the liquid .
ρghA=[2ρ(L2)A+ρ(L2)A]f where f=acceleration .⇒gh=3L2f⇒h=3f2gL