Question

A uniform chain of length 2m is kept on a table such that a length of 60cm hangs freely from the edge of the table. The total mass of the chain is 4kg .what is the work done in pulling the entire chain on the table

Answer 1

First of all let assume mas of chain hanging down is "m" while it's length is  "l".
Total length of chain "L"  while total mass is "M".
So from the given data we know that M is equal to 4kg
total length=L=2m
l = 60 cm = 0.6 m      As we know that 1 meter=100cm
 Thus we know that
m= I/L * M
m=(0.6/2 )* 4= 1.2kg 
In order to findout the tension of strain the formula is =mg
                                                                                      =1.2*10 = 12 Newton
we know that the tension is equal to force required and 0.6 is actually the displacement because that part is hanging
So  also we know
work done= force*displacement 
now as we have readings so just put the value 
Work done = 12 * 0.6 = 7.2 J
So the work done in this case will be equal to  7.2 J. 

Answer 2

Answer:

answer is 3.6J sorry dear i dont hav explanation