Question

A uniform circular path of width 2.5m is laid outside is circular park of radius 56 m. Find the cost of leveling the path at the rate of rupees 5 per sq. m

Answer 1

1368.75 ............
.......

Answer 2

Answer:

Rs.4494.125

Step-by-step explanation:

Refer the attached figure :

Radius of inner circle = 56 m

Area of circle = $\pi r^{2}$

Area of inner circle = $3.14 \times 56^{2}$

                                = $9847.04 m^2$

The width of the circular path is 2.5 m

So, the radius of the outer circle = inner radius +width = 56+2.5 =58.5 m

Area of outer circle = $3.14 \times 58.5^{2}$

                                = $10745.865 m^2$

So, area of path = Area of outer circle - Area of inner circle

                           = $10745.865-9847.04$

                           = $898.825m^2$

Now , Cost of leveling 1 square meter = Rs. 5

So, cost of leveling 898.825 square meter = 898.825 *5 = Rs.4494.125

Hence the cost of leveling the path is Rs.4494.125