A uniform cube of edge length 5 cm and and mass 5 kg kept on a tabletop. Find the pressure due to the cube on the table top on the portion where the cube touches the table top.
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Mass- (10×5)= 50N. (g=10m/s)
P=F/A
50/5÷100×5÷100
50/25×10000
2×10to the power 4 N/M square
P=F/A
50/5÷100×5÷100
50/25×10000
2×10to the power 4 N/M square
Answered by
1
Answer:
edge =5cm
=5/100 =0.05
m = 5kg
p=?
p=f/a
=mg/(edge)^2
p= 5×9.8/(0.05)^2
=5×9.8×10000/0.05×0.05
5×98×1000/ 25
=5×98×40
=19600 n/m^2
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