A uniform cube of side l and mass M rests on a rough horizontal table. A horizontal force F is applied normal to one of the faces at a point that is directly above the center of the face at a height 3l/4 above the base. Assuming that the cube may tip about an edge without slipping find the angular acceleration of the cube when F is equal to mg.
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here minimum force required
Fx3I/4=MgI/2
F = 2Mg/3
M * alpha = 2Mg/3
alpha (angular acceleration) =2*g/3 = 2*10/3 = 20/3 = 6.67
Fx3I/4=MgI/2
F = 2Mg/3
M * alpha = 2Mg/3
alpha (angular acceleration) =2*g/3 = 2*10/3 = 20/3 = 6.67
harsh3374chauhan:
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