A uniform cylinder length and diameters are measured as 10+_0.1cm and 4+_0.2 mm respectively. Then absolute error in volume
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Hey Dear,
◆ Answer -
Absolute error in volume = 0.1386 cm^3
● Explanation -
# Given -
l = 10 cm
∆l = 0.1 cm
d = 4 mm = 0.4 cm
∆d = 0.2 mm = 0.02 cm
# Solution -
Volume of the cylinder is given by -
V = A × l
V = π(d/2)^2 × l
V = π/4 d^2.l
V = 3.142/4 × 0.4^2 × 10
V = 1.26 cm^3
Thus, relative error in measurement of volume will be -
∆V/V = 2∆d/d + ∆l/l
∆V/V = 2 × 0.02 / 0.4 + 0.1/10
∆V/V = 0.1 + 0.01
∆V/V = 0.11
∆V = 0.11 × V
∆V = 0.11 × 1.26
∆V = 0.1386 cm^3
Hence, Absolute rror in measurement of volume is 0.1386 cm^3.
Thanks dear...
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