Question

A uniform electric field having a magnitude E
and direction along positive x-axis exists.If the
electric potential(V) is zero at x = 0 then its
value at x = + x will be
​

Answer 1

ans is in the attachments

Answer 2

Answer:

The electric potential at positive x axis is $V=-Ex$

Explanation:

Given that,

Electric field = E

The electric field is defined as,

$E =-\dfrac{dV}{dx}$....(I)

The electric potential is zero at x = 0.

Now, The electric potential at x = +x will be

From equation (I)

$E=-\dfrac{dV}{dx}$

Now the potential is given by

$dV=-Edx$

On integrating both side

$\int_{0}^{V}{dV}=-E\int_{0}^{x}{dx}$

$V=-E[x]_{0}^{x}$

$V=-Ex$

Hence, The electric potential at positive x axis will be $V=-Ex$