Question

A uniform electric field of 10 N C−1 exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.

Answer 1

The increase in the electric potential as one goes up through a height of 50 cm is 5 V.

Explanation:

Given values in the question :

             E = 10 n/c

             E is A uniform electric field

             Change in height, ds = 50 cm  

             "ds" is a height  

Converting height centimeter to meter  :

(i.e ) One centimeter is one-hundred  of a metre.

       It would take 100 cm long to equal a single meter in length .

                              $r=\frac{50}{100}=0.5 \mathrm{m}$

Change in electric potential, dv = E.ds    

                                               dv = 10×0.5

                                               dv = 5 v

Thus, 5V raise the electric potential as one climbs up to 50 cm in height.