Question

A uniform electric fiels A of 300 NC is directed along PQ . A B and B are three point in the field having x and y c ordinate in m . Calculate potential difference between the point A and B . And B and C

Answer 1

Given: A uniform electric fields A of 300 NC is directed along PQ.

To find: Calculate potential difference between the point A and B , B and C

Solution:

• Now we have given uniform electric fields A of 300 NC is directed along PQ.

• The points are A(4,1) , B(4,4) and C(-3,4).

1. Now distance between A and B is:

               d = √(4-4)^2 + (4-1)^2

               d = √3^2

               d = 2 m

• Now the potential difference will be:

               V = Ed

               V = 300 x 3

               V = 900 Volts.

     2. Now distance between B and C is:

               d = √(-3-4)^2 + (4-4)^2

               d = √-7^2

               d = 7 m

• Now the potential difference will be:

               V = Ed

               V = 300 x 7

               V = 2100 Volts.

Answer:

                 So the potential difference between the point A and B is 900 volts and B and C 2100 volts.

Answer 2

can u also say the potential difference between the points A and C