Physics, asked by majotpandher39261, 11 months ago

A uniform field of 1 wb/m^2 a direct current of 70a is passed through a straight wire of 1.5 m placed perpendicular to the field the prime movwr power in watt to displace the conductor against force at unisorm velocity of 5m/s

Answers

Answered by subashc656
0

Answer:

uniform field of 1 wb/m^2 a direct current of 70a is passed through a straight wire of 1.5 m placed perpendicular to the field the prime movwr power in watt to displace the conductor against force at unisorm velocity of 5m/sthe stopping potential for a given photosensitive surface go out with the frequency of incident radiation what to be increased from 400 to 15 hertz to 818 minutesthe stopping potential for a given photosensitive surface go out with the frequency of incident radiation what to be increased from 400 to 15 hertz to 818 minutesA vessel with 120ml capacity contains a certain amount of gas at 35°c and 1.2 bar pressure. Thr gas is transferred to another vessel of volumeInnocence Olympic 5 marks are given for each correct answer and -2 for each in correct answer Sumit and stirred all the question and scored 26 marks throw the got to incorrect answer howthe stopping potential for a given photosensitive surface go out with the frequency of incident radiation what to be increased from 400 to 15 hertz to 818 minutes

Answered by SmritiSami
0

The power in watt to displace the conductor against the force is 525W.

Given:-

Magnetic Field (B) = 1wb/m²

Current (i) = 70A

Length (l) = 1.5m

Angle = 90°

Velocity (v) = 5m/s

To Find:-

The power in watt to displace the conductor against the force.

Solution:-

To find power, you need to follow the simple steps which includes the following.

Now,

Magnetic Field (B) = 1wb/m²

Current (i) = 70A

Length (l) = 1.5m

Angle = 90°

Velocity (v) = 5m/s

Power (P) = ?

According to the formula,

P = F* V

F =

b \times i \times l \times  \sin(90)

P =

b \times i \times l \:  \sin(90)  \times v

P =

b \times i \times l \times v \times 1

P =

1 \times 70 \times 1.5 \times 5 \times 1

P = 525W

Hence, The power in watt to displace the conductor against the force is 525W.

#SPJ2

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