Question

A uniform flexible chain of mass m and length 2l hangs in equilibrium over a smooth horizontal pin of negligible diameter.

Answer 1

The question is incomplete.

However,

Given:

Mass = m

Length = 2l

Equilibrium

Diameter negligible.

To find:

The speed of the chain

Solution:

By law,

There is an increase in kinetic energy with decrease in potential energy.

Hence,

Speed = m * g ( l - l /2 )

We get,

m g l / 2

Where,

m - mass

g - gravity

l - length

Substituting the values,

1 / 2 m v^2

Speed = √ gl

The answer is √ gl